A quick explanation of the VC dimension.
When talking about binary classification, an
hypothesis is a function that maps an input from the entire
input space to a result: h:X→{−1,+1}
A dichotomy is a hypothesis that maps from an input from the sample size to a result:
h:{x1,x2,…,xN}→{−1,+1}
The number of dichotomies |H(x1,x2,…,xN)| is at most 2N, where N is the sample size.
e.g. for a sample size N=3 we have at most 8 possible dichotomies:
x1 x2 x3
1 -1 -1 -1
2 -1 -1 +1
3 -1 +1 -1
4 -1 +1 +1
5 +1 -1 -1
6 +1 -1 +1
7 +1 +1 -1
8 +1 +1 +1
The growth function is a function that counts the
most dichotomies on any N
points. mH(N)=maxx1,…,xN∈X|H(x1,…,xN)|
The growth function satisfies: mH(N)≤2N
This is where the perceptron breaks down because it cannot separate that configuration, and so mH(4)=14 because two configurations—this one and the one in which the left/right points are blue and top/bottom are red—cannot be represented. For this reason, we have to expect that for perceptrons, m can’t be 24.
The VC ( Vapnik-Chervonenkis ) dimension of a hypothesis set H , denoted by dVC(H) is the largest value of N for which mH(N)=2N , in other words is “the most points H can shatter”
We can say that the VC dimension is one of many measures that characterize the expressive power, or capacity, of a hypothesis class.
You can think of the VC dimension as “how many points can this model class memorize/shatter?” (a ton? → BAD! not so many? → GOOD!).
With respect to learning, the effect of the VC dimension is that if the VC dimension is finite, then the hypothesis will generalize:
dvc(H) ⟹ g∈H will
generalize
The key observation here is that this statement is independent of:
The only things that factor into this are the training examples, the hypothesis set, and the final hypothesis.
The VC dimension for a linear classifier (i.e. a line in 2D, a plane in 3D etc…) is d+1 (a line can shatter at most 2+1=3 points, a plane can shatter at most 3+1=4 points etc…)
Proof: here
How many randomly drawn examples suffice to guarantee error of at most ϵ with probability at least (1−δ)?
N≥1ϵ(4log(2δ)+8VC(H)log2(13ϵ))
PAC BOUND using VC dimension: Ltrue(h)≤Ltrain(h)+√VC(H)(ln2NVC(H)+1)+ln4δN
For attribution, please cite this work as
Bonvini (2021, Feb. 14). Last Week's Potatoes: The VC dimension.. Retrieved from https://lastweekspotatoes.com/posts/2021-07-22-the-vc-dimension/
BibTeX citation
@misc{bonvini2021the, author = {Bonvini, Andrea}, title = {Last Week's Potatoes: The VC dimension.}, url = {https://lastweekspotatoes.com/posts/2021-07-22-the-vc-dimension/}, year = {2021} }